Issue 34803: argparse int type does not accept scientific notation

The 'argparse' module gives a parse error for integer arguments written in scientific notation. I would expect this to work, since integers can be constructed from literals in scientific notation.

Example (also attached):

import argparse
foo = int(1e3) # Works: foo = 1000
parser = argparse.ArgumentParser()
parser.add_argument( "--foo", type=int )
parser.parse_args( ["--foo=1e3"] )
# error: argument --foo: invalid int value: '1e3'

I suppose desired behavior would be to accept the argument only if it can be converted to int without loss of information.

The conversion fails because is trying to convert a string, not a float:

>>> int("1e3")
*** ValueError: invalid literal for int() with base 10: '1e3'

You can always do:

import argparse
foo = int(1e3) # Works: foo = 1000
parser = argparse.ArgumentParser()
parser.add_argument( "--foo", type=lambda x: int(float(x)))
parser.parse_args( ["--foo=1e3"] )

The `type` parameter is normally a function (or more generally a callable).  When given a string it should convert it as needed, or raise an error.  In your example that function is the stock, 'int()'.

Test `int('123')`, `int('1e3')` etc for yourself to see what it can handle.

If you want to convert '1e3' to an integer, write your own function that handle it.  Don't expect argparse or the stock int() to do it for you.

More commonly people use 'type=bool', expecting it convert 'True' or 'False' strings to boolean values.  But that's not what the bool() function does.

To reiterate, 'type' is a function, not a desired class.

Since this is not a bug, I think this should be closed.